5x^2+32xy+12y^2=0

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Solution for 5x^2+32xy+12y^2=0 equation:


Simplifying
5x2 + 32xy + 12y2 = 0

Reorder the terms:
32xy + 5x2 + 12y2 = 0

Solving
32xy + 5x2 + 12y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(5x + 2y)(x + 6y) = 0

Subproblem 1

Set the factor '(5x + 2y)' equal to zero and attempt to solve: Simplifying 5x + 2y = 0 Solving 5x + 2y = 0 Move all terms containing x to the left, all other terms to the right. Add '-2y' to each side of the equation. 5x + 2y + -2y = 0 + -2y Combine like terms: 2y + -2y = 0 5x + 0 = 0 + -2y 5x = 0 + -2y Remove the zero: 5x = -2y Divide each side by '5'. x = -0.4y Simplifying x = -0.4y

Subproblem 2

Set the factor '(x + 6y)' equal to zero and attempt to solve: Simplifying x + 6y = 0 Solving x + 6y = 0 Move all terms containing x to the left, all other terms to the right. Add '-6y' to each side of the equation. x + 6y + -6y = 0 + -6y Combine like terms: 6y + -6y = 0 x + 0 = 0 + -6y x = 0 + -6y Remove the zero: x = -6y Simplifying x = -6y

Solution

x = {-0.4y, -6y}

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